An m-order n-dimensional tensor is a Q tensor if the tensor complementarity problem TCP(q,A)has a solution for any vector q ∈Rn.That is,for any vector q,there exists a vector u such thatu≥0,w=Aum-1+q≥0 anduTw=0.Based on[1],this paper further studies whether the Q-tensor of symmetric ranksym(A)=3 is R0-tensor.Studying A∈S(3,2)has the same conclusion as[1],but for the tensor of symmetric ranksym(A)=3,TCP(0,A)has a non-zero solution in the tensor comple-mentarity problem,which is worthy of further study.
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