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用折线法确定避雷针保护范围的防雷漏洞与改进

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用现行折线法确定避雷针高度为h的保护范围,由于没有考虑h的有效保护范围的影响,单支h及两支等高h之间的保护范围均存在防雷漏洞.分析了这些防雷漏洞,并对折线法进行了改进:设h=30m时h在0.5h高度处的有效保护半径为rh/2=15 m,h的圆锥体及圆台体保护范围的地面有效保护半径分别为r01=30 m,r02=45 m,推导出当h>30m时,h对圆锥体的保护角α'及h在任意高度处的保护半径rx的计算公式;取D<2r01 或D<2r02 限制两支等高h的针间距离,按h0=r01或h0=r02为半径的圆弧确定两支等高h的针间保护范围.改进后随着h的增高,α'减小,rh/2、r01、r02 保持不变,单支h的保护范围被拉高变窄,单支h及两支等高h之间的保护范围均在h的有效保护范围之内,有效堵住了折线法的防雷漏洞.
Lightning Protection Loopholes and Improvement of Determining the Protection Range of Lightning Rod by Broken Line Method
The current broken line method is used to determine the protection range of lightning rod with a height of h,because the effective protection range of h is not considered,there are lightning protection loopholes protection range of between single h and two equal height h.This paper analyzes these lightning protection loopholes,and improves the broken line method:When h=30 m,the effective protection radius of h at a height of 0.5h is rh/2=15 m,and the effective protection radius of the ground of the protection range of cone body and roundtable body of h are respectively r01=30 m and r02=45 m.The formula for calculating the protection angle α'of h to the cone body when h>30 m and the protection radius rx of h at any height are derived.Take D<2 r01 or D<2 r02 to limit the distance between the two equal height h,and determine the protection range between the two equal height h according to the arc of h0=r01 or h0=r02 as the radius.After the improvement,with the increase of h,α'decreases,rh/2,r01 and r02 remain unchanged,and the protection range of single h is increased and narrowed,and the protection range between single h and two equal-height h is within the effective protection range of h,effectively blocking the lightning protection loophole of the broken line method.

lightning rodprotection angleheight influence coefficientbroken line methodprotection rangethunderbolt flashover distance

郑江、林苗

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广西大学电气工程学院,广西南宁 530004

避雷针 保护角 高度影响系数 折线法 保护范围 雷闪距离

2024

现代建筑电气
上海电器科学研究所(集团)有限公司

现代建筑电气

影响因子:0.712
ISSN:1674-8417
年,卷(期):2024.15(5)
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